1876 United States presidential election in Vermont information
Election in Vermont
Main article: 1876 United States presidential election
1876 United States presidential election in Vermont
← 1872
November 7, 1876
1880 →
Nominee
Rutherford B. Hayes
Samuel J. Tilden
Party
Republican
Democratic
Home state
Ohio
New York
Running mate
William A. Wheeler
Thomas A. Hendricks
Electoral vote
5
0
Popular vote
44,091
20,254
Percentage
68.30%
31.38%
County Results
Hayes
50–60%
60–70%
70–80%
80–90%
President before election
Ulysses S. Grant
Republican
Elected President
Rutherford B. Hayes
Republican
Elections in Vermont
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U.S. House elections
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v
t
e
The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.
With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote.[1]
^"1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
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