1932 United States presidential election in Vermont information
Election in Vermont
Main article: 1932 United States presidential election
1932 United States presidential election in Vermont
← 1928
November 8, 1932
1936 →
Nominee
Herbert Hoover
Franklin D. Roosevelt
Party
Republican
Democratic
Home state
California
New York
Running mate
Charles Curtis
John N. Garner
Electoral vote
3
0
Popular vote
78,984
56,266
Percentage
57.66%
41.08%
County results
Municipality results
Hoover
40-50%
50-60%
60-70%
70-80%
80-90%
90-100%
Roosevelt
40-50%
50-60%
60-70%
70-80%
80-90%
90-100%
Tie
40-50%
President before election
Herbert Hoover
Republican
Elected President
Franklin D. Roosevelt
Democratic
Elections in Vermont
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v
t
e
The 1932 United States presidential election in Vermont took place on November 8, 1932, as part of the 1932 United States presidential election which was held throughout all contemporary 48 states. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Vermont voted for the Republican nominee, incumbent President Herbert Hoover of California, over the Democratic nominee, Governor Franklin D. Roosevelt of New York. Hoover's running mate was incumbent Vice President Charles Curtis of Kansas, while Roosevelt ran with incumbent Speaker of the House John Nance Garner of Texas.
Hoover took 57.66% of the vote to Roosevelt’s 41.08%, a margin of 16.58%. Vermont historically was a bastion of Northeastern Republicanism, and by 1932 it had gone Republican in every presidential election since the founding of the Republican Party. From 1856 to 1928, Vermont had had the longest streak of voting Republican of any state, having never voted Democratic before, and this tradition continued even in the midst of a nationwide Democratic landslide in 1932.
Vermont was one of only six states (the other five states being Connecticut, Delaware, neighboring New Hampshire, Maine and Pennsylvania), four of them in New England, which voted to re-elect the embattled Republican incumbent Hoover, who was widely unpopular over his failure to adequately address the Great Depression. Vermont would ultimately be one of only two states (along with nearby Maine) that would reject FDR in all four of his presidential campaigns.
In terms of both vote share and margin, Vermont was the most Republican state in the nation.[1] Vermont would weigh in as a whopping 34% more Republican than the national average in the 1932 election. However, Roosevelt was the first Democrat to get over 40% of the vote in the state since 1836.
Hoover carried eleven of the state’s 14 counties, breaking sixty percent in seven. However, the three northwestern counties of Vermont would become New Deal Democratic enclaves in an otherwise Republican state. In 1928, Al Smith had become the first ever Democrat to win Chittenden County,[2] the state’s most populous county and home to its largest city, Burlington. In 1932, Roosevelt would carry Chittenden County for the Democrats as Smith did in 1928, but also flip Franklin County and Grand Isle County into the Democratic column. All three counties would remain loyally Democratic in the elections that followed until Dwight D. Eisenhower’s Republican landslide of 1952.[3]
^"1932 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
^Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, p. 60 ISBN 0786422173
^Menendez; The Geography of Presidential Elections in the United States, pp. 321-322
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