1876 United States presidential election in Rhode Island information
Election in Rhode Island
Main article: 1876 United States presidential election
1876 United States presidential election in Rhode Island
← 1872
November 7, 1876
1880 →
Nominee
Rutherford B. Hayes
Samuel J. Tilden
Party
Republican
Democratic
Home state
Ohio
New York
Running mate
William A. Wheeler
Thomas A. Hendricks
Electoral vote
4
0
Popular vote
15,787
10,712
Percentage
59.29%
40.23%
County Results
Hayes
50-60%
60-70%
President before election
Ulysses S. Grant
Republican
Elected President
Rutherford B. Hayes
Republican
Elections in Rhode Island
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Question 1
Providence
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v
t
e
The 1876 United States presidential election in Rhode Island took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Rhode Island voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won the state by a margin of 19.06%.
With 59.29% of the popular vote, Rhode Island would be Hayes' fourth strongest victory in terms of percentage in the popular vote after Vermont, Nebraska and Kansas.[1]
This was the only election between 1860 and 1888 where the Democratic candidate earned more than 40% statewide, as well as the only election in the same period where the Democratic candidate earned more than 40% in at least one Rhode Island county.
^"1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
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