In mathematics, the commutator subspace of a two-sided ideal of bounded linear operators on a separable Hilbert space is the linear subspace spanned by commutators of operators in the ideal with bounded operators.
Modern characterisation of the commutator subspace is through the Calkin correspondence and it involves the invariance of the Calkin sequence space of an operator ideal to taking Cesàro means. This explicit spectral characterisation reduces problems and questions about commutators and traces on two-sided ideals to (more resolvable) problems and conditions on sequence spaces.
and 28 Related for: Commutator subspace information
the commutatorsubspace of a two-sided ideal of bounded linear operators on a separable Hilbert space is the linear subspace spanned by commutators of...
trace-class operators, Kalton developed a spectral condition for the commutatorsubspace of trace class operators following on from results of Gary Weiss...
Introduction to Boolean Algebras, Springer. Crinkled arc Commutatorsubspace Invariant subspace problem Naive set theory Criticism of non-standard analysis...
if and only if all its coefficients are zero. Linear subspace A linear subspace or vector subspace W of a vector space V is a non-empty subset of V that...
linear subspace spanned by all brackets [ x , y ] {\displaystyle [x,y]} with x , y ∈ g {\displaystyle x,y\in {\mathfrak {g}}} . The commutator subalgebra...
Poisson brackets. In quantum mechanics, it is satisfied by operator commutators on a Hilbert space and equivalently in the phase space formulation of...
bracket [ X , Y ] := X Y − Y X {\displaystyle [X,Y]:=XY-YX} given by the commutator. This algebra is well studied and understood, and is often used as a model...
the commutator of the creation and annihilation operators that are associated with the same boson state equals one, while all other commutators vanish...
subspace of the complexified tangent space of M {\displaystyle M} . The subspaces should form an integrable distribution, meaning that the commutator...
group. They do, however, form a loop, specifically a Moufang loop. The commutator of two octonions x and y is given by [ x , y ] = x y − y x . {\displaystyle...
of a vector space) in such a way that the Lie bracket is given by the commutator. In the language of physics, one looks for a vector space V {\displaystyle...
identified with the 3-sphere. Its Lie algebra is the subspace of quaternion vectors. Since the commutator ij − ji = 2k, the Lie bracket in this algebra is...
a blade may be used to represent a subspace of V {\displaystyle V} and orthogonal projections onto that subspace. Rotations and reflections are represented...
important quantity is the commutator. For a pair of operators  and B ^ {\displaystyle {\hat {B}}} , one defines their commutator as [ A ^ , B ^ ] = A ^...
on a topological space X {\displaystyle X} is a collection of linear subspaces U x {\displaystyle U_{x}} of the fibers V x {\displaystyle V_{x}} of V...
construction involves (perhaps only implicitly) the choice of a maximal isotropic subspace in the vector representation of the group. Over the real numbers, this...
bracket operation in g {\displaystyle {\mathfrak {g}}} corresponds to the commutator x y − y x {\displaystyle xy-yx} in A {\displaystyle {\mathcal {A}}} and...
This is related to the octonions over the imaginary subspace Im(O) in 7-space whose commutator between two octonions defines this vector product, wherein...
unital associative algebra with the additional structure of a distinguished subspace. As K-algebras, they generalize the real numbers, complex numbers, quaternions...
{\displaystyle {\mathfrak {gl}}_{n},} consists of all n×n real matrices with the commutator serving as the Lie bracket. As a manifold, GL(n, R) is not connected but...
Commutator (group theory): if a and b belong to a group, then [ a , b ] = a − 1 b − 1 a b {\displaystyle [a,b]=a^{-1}b^{-1}ab} . 3. Commutator (ring...
{\displaystyle A} and B {\displaystyle B} are bounded operators with trace-class commutator A B − B A {\displaystyle AB-BA} , then det e A e B e − A e − B = exp ...
the identity, and the Lie bracket of the Lie algebra is related to the commutator of two such infinitesimal elements. Before giving the abstract definition...
j ] {\displaystyle [A_{i},A_{j}]} is the commutator; for commuting A i {\displaystyle A_{i}} the commutator vanishes so this holds. This was proven by...
multiplication. This doesn't hold for the matrix commutator and also there is no identity element for the commutator. Hence for Lie algebras, the only requirement...
functions on a circle (interpreted as the closed string) with pointwise commutator. The affine Lie algebra g ^ {\displaystyle {\hat {\mathfrak {g}}}} is...
expression for Z = log(eXeY) in terms of a series expansion of nested commutators of X and Y. This general expansion unfolds as Z = C ( X , Y ) = X + Y...
introduced by Nathan Jacobson in 1949 to study subspaces of associative algebras closed under triple commutators [[u, v], w] and triple anticommutators {u...