1836 United States presidential election in Vermont information
Election in Vermont
Main article: 1836 United States presidential election
1836 United States presidential election in Vermont
← 1832
November 3 - December 7, 1836
1840 →
Nominee
William Henry Harrison
Martin Van Buren
Party
Whig
Democratic
Home state
Ohio
New York
Running mate
Francis Granger
Richard Mentor Johnson
Electoral vote
7
0
Popular vote
20,994
14,037
Percentage
59.93%
40.07%
County results
Harrison
50-60%
60-70%
70-80%
Van Buren
50-60%
President before election
Andrew Jackson
Democratic
Elected President
Martin Van Buren
Democratic
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Preview warning: Page using Template:Infobox election with unknown parameter "before_color"
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v
t
e
The 1836 United States presidential election in Vermont took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Vermont voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 19.86%.
This would be the final time a Democratic candidate would carry Essex County until Franklin D. Roosevelt won it 104 years later in 1940.
1836 would stand as the strongest performance for a Democratic candidate in Vermont until 96 years later in 1932, when Franklin D. Roosevelt performed slightly better with 41.08%.
Harrison would later win Vermont again four years later when he successfully defeated Van Buren.
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