1884 United States presidential election in Vermont information
Election in Vermont
Main article: 1884 United States presidential election
1884 United States presidential election in Vermont
← 1880
November 4, 1884
1888 →
Nominee
James G. Blaine
Grover Cleveland
Party
Republican
Democratic
Home state
Maine
New York
Running mate
John A. Logan
Thomas A. Hendricks
Electoral vote
4
0
Popular vote
39,514
17,331
Percentage
66.52%
29.18%
County Results
Blaine
50-60%
60-70%
70-80%
80-90%
President before election
Chester A. Arthur
Republican
Elected President
Grover Cleveland
Democratic
Elections in Vermont
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U.S. House elections
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v
t
e
The 1884 United States presidential election in Vermont took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Vermont voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Vermont by a margin of 37.34%.
With 66.52% of the popular vote, Vermont would be Blaine's strongest victory in terms of percentage in the popular vote.[1]
^"1884 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
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