1884 United States presidential election in Maryland information
U.S. presidential election in Maryland
Main article: 1884 United States presidential election
1884 United States presidential election in Maryland
← 1880
November 4, 1884
1888 →
Nominee
Grover Cleveland
James G. Blaine
Party
Democratic
Republican
Home state
New York
Maryland
Running mate
Thomas A. Hendricks
John A. Logan
Electoral vote
8
0
Popular vote
96,866
85,748
Percentage
52.07%
46.10%
County Results
Cleveland
40-50%
50-60%
60-70%
Blaine
40-50%
50-60%
President before election
Chester A. Arthur
Republican
Elected President
Grover Cleveland
Democratic
Elections in Maryland
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1998
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Ballot measures
Question P
Government
v
t
e
The 1884 United States presidential election in Maryland took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.
Maryland voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. by a margin of 5.98%.[1]
In this election, Maryland voted 5.41% more Democratic than the nation at-large.[2]
^Humanities, National Endowment for the (November 19, 1884). "Evening capital. (Annapolis, Md.) 1884-1910, November 19, 1884, Image 1". ISSN 2643-8593. Retrieved November 29, 2021.
^"Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved March 31, 2023.
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