1976 United States presidential election in Rhode Island information
Election in Rhode Island
Main article: 1976 United States presidential election
1976 United States presidential election in Rhode Island
← 1972
November 2, 1976
1980 →
Turnout
76.4%[1]
Nominee
Jimmy Carter
Gerald Ford
Party
Democratic
Republican
Home state
Georgia
Michigan
Running mate
Walter Mondale
Bob Dole
Electoral vote
4
0
Popular vote
227,636
181,249
Percentage
55.36%
44.08%
County Results
Municipality Results
Carter
40–50%
50–60%
60–70%
Ford
40–50%
50–60%
60–70%
President before election
Gerald Ford
Republican
Elected President
Jimmy Carter
Democratic
Elections in Rhode Island
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Question 1
Providence
Mayoral elections
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v
t
e
The 1976 United States presidential election in Rhode Island took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.
Rhode Island was won by Jimmy Carter (D–Georgia), with 55.36% of the popular vote. Carter defeated incumbent President Gerald Ford (R–Michigan), who finished with 44.08% of the popular vote. No third-party candidate received any votes.
Jimmy Carter went on to become the 39th president of the United States.[2]
^This figure is calculated by dividing the total number of votes cast in 1976 (416,583) by an estimate of the number of registered voters in Rhode Island in 1976 (544,992). See "General Election November 2, 1976". Rhode Island Board of Elections. Retrieved February 6, 2018.
^"Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved February 11, 2024.
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