1868 United States presidential election in Maryland information
Election in Maryland
Main article: 1868 United States presidential election
1868 United States presidential election in Maryland
← 1864
November 3, 1868
1872 →
Nominee
Horatio Seymour
Ulysses S. Grant
Party
Democratic
Republican
Home state
New York
Illinois
Running mate
Francis Preston Blair, Jr.
Schuyler Colfax
Electoral vote
7
0
Popular vote
62,357
30,438
Percentage
67.20%
32.80%
County Results
Seymour
50-60%
60-70%
70-80%
80-90%
90-100%
Grant
50-60%
President before election
Andrew Johnson
Democratic
Elected President
Ulysses S. Grant
Republican
Elections in Maryland
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U.S. House of Representatives elections
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State government
General elections
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Ballot measures
Question P
Government
v
t
e
The 1868 United States presidential election in Maryland took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
Maryland voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a margin of 34.4%.
In this election, Maryland voted 39.72% more Democratic than the nation at-large.[1]
With 67.2% of the popular vote, Maryland would be Seymour's third strongest victory in terms of percentage in the popular vote after Kentucky and Louisiana.[2] To date this is the best performance by a Democrat in Maryland history.
This was the first presidential election that Wicomico County was able to vote in.
^"Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved April 6, 2023.
^"1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
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