1868 United States presidential election in Delaware information
Election in Delaware
Main article: 1868 United States presidential election
1868 United States presidential election in Delaware
← 1864
November 3, 1868
1872 →
Nominee
Horatio Seymour
Ulysses S. Grant
Party
Democratic
Republican
Home state
New York
Illinois
Running mate
Francis Preston Blair, Jr.
Schuyler Colfax
Electoral vote
3
0
Popular vote
10,957
7,614
Percentage
59.00%
41.00%
County Results
Seymour
50-60%
60-70%
President before election
Andrew Johnson
Democratic
Elected President
Ulysses S. Grant
Republican
Elections in Delaware
Federal government
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v
t
e
The 1868 United States presidential election in Delaware took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Delaware voted for the Democratic nominee, Horatio Seymour, over the Republican nominee, Ulysses S. Grant. Seymour won the state by a margin of 18%.
With 59% of the popular vote, Delaware would prove to be Seymour's fifth strongest state in terms of popular vote percentage after Kentucky, Louisiana, Maryland and Georgia.[1]
^"1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
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