1804 United States presidential election in Delaware information
Election in Delaware
Main article: 1804 United States presidential election
1804 United States presidential election in Delaware
← 1800
2 November – 5 December 1804
1808 →
Nominee
Charles C. Pinckney
Thomas Jefferson
Party
Federalist
Democratic-Republican
Home state
South Carolina
Virginia
Running mate
Rufus King
George Clinton
Electoral vote
3
0
Elections in Delaware
Federal government
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Wilmington
Mayoral elections
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v
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The 1804 United States presidential election in Delaware took place between 2 November and 5 December 1804, as part of the 1804 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Delaware cast three electoral votes for the Federalist candidate Charles C. Pinckney over the Democratic-Republican candidate and incumbent President Thomas Jefferson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York.[1]
^"1804 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
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