1804 United States presidential election information
5th quadrennial U.S. presidential election
1804 United States presidential election
← 1800
November 2 – December 5, 1804
1808 →
176 members of the Electoral College 89 electoral votes needed to win
Turnout
23.8%[1] 8.5 pp
Nominee
Thomas Jefferson
Charles C. Pinckney
Party
Democratic-Republican
Federalist
Home state
Virginia
South Carolina
Running mate
George Clinton
Rufus King
Electoral vote
162
14
States carried
15
2
Popular vote
104,110
38,919
Percentage
72.8%
27.2%
Presidential election results map. Green denotes states won by Jefferson and Orange denotes states won by Pinckney. Numbers indicate the number of electoral votes cast by each state.
President before election
Thomas Jefferson
Democratic-Republican
Elected President
Thomas Jefferson
Democratic-Republican
The 1804 United States presidential election was the fifth quadrennial presidential election, held from Friday, November 2, to Wednesday, December 5, 1804. Incumbent Democratic-Republican president Thomas Jefferson defeated Federalist Charles Cotesworth Pinckney of South Carolina. It was the first presidential election conducted following the ratification of the Twelfth Amendment to the United States Constitution, which reformed procedures for electing presidents and vice presidents.
Jefferson was re-nominated by his party's congressional nominating caucus without opposition, and the party nominated Governor George Clinton of New York to replace Aaron Burr as Jefferson's running mate. With former president John Adams in retirement, the Federalists turned to Pinckney, a former ambassador and Revolutionary War hero who had been Adams's running mate in the 1800 election.
Though Jefferson had only narrowly defeated Adams in 1800, he was widely popular due to the Louisiana Purchase and a strong economy. He carried almost every state, including most states in the Federalist stronghold of New England.
^"National General Election VEP Turnout Rates, 1789-Present". United States Election Project. CQ Press.
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