The 2018 Shoot Out (officially the 2018 Coral Snooker Shoot Out) was a professional ranking snooker tournament, that took place from 8–11 February 2018 in Watford, England.[1] It was played under a variation of the standard rules of snooker,[2] and was the fourteenth ranking event of the 2017/2018 season.
Anthony McGill was the defending champion, but he lost to Mark Davis in the first round, after Davis made a break of 102.[3][4]
Michael Georgiou won his first ever ranking title, beating Graeme Dott 67–56 in the final.[5][6] None of the top five players in the world rankings at the time, (Mark Selby, Ronnie O'Sullivan, Judd Trump, Ding Junhui and John Higgins) had entered the tournament.[7]
^"2017/18 World Snooker Calendar" (PDF). World Professional Billiards and Snooker Association. 14 July 2017. Retrieved 14 July 2017.
^Ramage, Ben (7 April 2018). "Totten aiming to beat the clock and take big scalps at Snooker Shoot-Out". dailyrecord.co.uk. Retrieved 19 April 2022.
^"Match Result - World Snooker Live Scores". livescores.worldsnookerdata.com. Archived from the original on 9 February 2018. Retrieved 8 February 2018.
^Newstead, Simon (8 February 2018). "Ton-up Davis beats defending champ". Bexhill-on-Sea Observer.
^"Georgiou Wins Maiden Title In Dott Thriller". World Snooker. 11 February 2018. Retrieved 12 February 2018.
^"Georgiou takes the win in Shoot Out final". 12 February 2018. p. 36.
^"McGill: I got my shot at Shoot Out glory". The Daily Record. 8 February 2018. p. 55.
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