1996 United States presidential election in Hawaii information
Election in Hawaii
Main article: 1996 United States presidential election
1996 United States presidential election in Hawaii
← 1992
November 5, 1996
2000 →
Nominee
Bill Clinton
Bob Dole
Ross Perot
Party
Democratic
Republican
Reform
Home state
Arkansas
Kansas
Texas
Running mate
Al Gore
Jack Kemp
Pat Choate
Electoral vote
4
0
0
Popular vote
205,012
113,943
27,358
Percentage
56.93%
31.64%
7.60%
County Results
Clinton
50–60%
60–70%
70–80%
President before election
Bill Clinton
Democratic
Elected President
Bill Clinton
Democratic
Elections in Hawaii
Federal government
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v
t
e
The 1996 United States presidential election in Hawaii took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.
Hawaii was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 56.93% to 31.64% by a margin of 25.29%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 7.6% of the popular vote.[1]
^Leip, David. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved June 14, 2018.
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