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1988 United States presidential election in Florida information


1988 United States presidential election in Florida
1988 United States presidential election in Florida
← 1984 November 8, 1988 1992 →
TurnoutDecrease71%[1]
 
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 21 0
Popular vote 2,618,885 1,656,701
Percentage 60.87% 38.51%

County Results

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

The 1988 United States presidential election in Florida took place on November 8, 1988.[2] All fifty states and the District of Columbia, were part of the 1988 United States presidential election. Florida voters chose twenty-one electors to the Electoral College, which selected the president and vice president.

Florida was won by incumbent Vice President George H. W. Bush, running with U.S Senator Dan Quayle, against Governor Michael Dukakis, running with U.S. Senator Lloyd Bentsen. This was Bush's fifth strongest state in the 1988 election after Utah, New Hampshire, Idaho and South Carolina.[3]

Bush won every county in the state, with the exception for North Florida’s majority-black Gadsden County, which voted for Dukakis. As of the 2020 presidential election, this is the last election in which Miami-Dade County, Broward County, Palm Beach County, Alachua County, and Leon County voted for a Republican presidential candidate.[4]

  1. ^ Moreland, Steed & Baker 1991, p. 176.
  2. ^ "Voter Turnout". Florida Division of Elections. 2021. Archived from the original on June 2, 2015.
  3. ^ "1988 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  4. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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