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1976 United States presidential election in Wyoming information


1976 United States presidential election in Wyoming
1976 United States presidential election in Wyoming
← 1972 November 2, 1976 1980 →
 
Nominee Gerald Ford Jimmy Carter
Party Republican Democratic
Home state Michigan Georgia
Running mate Bob Dole Walter Mondale
Electoral vote 3 0
Popular vote 92,717 62,239
Percentage 59.30% 39.81%

County Results

President before election

Gerald Ford
Republican

Elected President

Jimmy Carter
Democratic

The 1976 United States presidential election in Wyoming took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Wyoming was won by incumbent President Gerald Ford (R–Michigan), with 59.30% of the popular vote, against Jimmy Carter (D–Georgia), with 39.81% of the popular vote. Carter's vote would be the highest percent received by a Democrat since Lyndon Johnson's victory 1964, and, as of 2020, remains the highest percentage a Democrat has received in the period since then (Bill Clinton came closer to winning the state in terms of margin of victory in 1992 and 1996, though with a reduced percentage due to the strong third party candidacy of Ross Perot). Despite losing in Wyoming, Carter went on to win the national election and became the 39th president of the United States.[1] With 59.3 percent of the popular vote, Wyoming would prove to be Ford's third strongest state in the 1976 election after neighboring Utah and Idaho.[2] This was the first time Laramie County voted for a losing candidate since 1892.

  1. ^ Dave Leip's U.S. Election Atlas; 1976 Presidential General Election Results – Wyoming
  2. ^ "1976 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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