1968 United States presidential election in Nebraska information
Election in Nebraska
Main article: 1968 United States presidential election
1968 United States presidential election in Nebraska
← 1964
November 5, 1968[1]
1972 →
Nominee
Richard Nixon
Hubert Humphrey
George Wallace
Party
Republican
Democratic
American Independent
Home state
New York[a]
Minnesota
Alabama
Running mate
Spiro Agnew
Edmund Muskie
S. Marvin Griffin
Electoral vote
5
0
0
Popular vote
321,163
170,784
44,904
Percentage
59.82%
31.81%
8.36%
County Results
Nixon
40-50%
50-60%
60-70%
70-80%
80-90%
Humphrey
40-50%
President before election
Lyndon B. Johnson
Democratic
Elected President
Richard Nixon
Republican
Elections in Nebraska
Federal offices
Presidential elections
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State government
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Gubernatorial elections
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Lieutenant Gubernatorial elections
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Government
v
t
e
The 1968 United States presidential election in Nebraska took place on November 5, 1968, as part of the 1968 United States presidential election. Voters chose five[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Nebraska was won by the Republican candidate former Vice President Richard Nixon, with 59.82% of the popular vote, against the Democratic candidate former Senator and incumbent Vice President Hubert Humphrey, with 31.81% of the popular vote. American candidate George Wallace performed decently, finishing with 8.36% of the popular vote.[3][4]
With 59.82% of the popular vote, Nebraska would prove to be Nixon's best state in the election,[5] just as it had been eight years earlier.
^"United States Presidential election of 1968 - Encyclopædia Britannica". Retrieved May 25, 2017.
^"1968 Election for the Forty-Sixth Term (1969-73)". Retrieved May 25, 2017.
^"1968 Presidential General Election Results – Nebraska". Retrieved May 25, 2017.
^"The American Presidency Project – Election of 1968". Retrieved May 25, 2017.
^"1968 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
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