1948 United States presidential election in Montana information
Election in Montana
Main article: 1948 United States presidential election
1948 United States presidential election in Montana
← 1944
November 2, 1948
1952 →
Nominee
Harry S. Truman
Thomas E. Dewey
Party
Democratic
Republican
Home state
Missouri
New York
Running mate
Alben W. Barkley
Earl Warren
Electoral vote
4
0
Popular vote
119,071
96,770
Percentage
53.09%
43.15%
County Results
Truman
40-50%
50-60%
60-70%
Dewey
40-50%
50-60%
60-70%
President before election
Harry S. Truman
Democratic
Elected President
Harry S. Truman
Democratic
Elections in Montana
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v
t
e
The 1948 United States presidential election in Montana took place on November 2, 1948 as part of the 1948 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Montana voted for the Democratic nominee, President Harry S. Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a substantial margin of 9.94%. As of the 2020 presidential election[update], this is the last election in which Carter County and Prairie County voted for a Democratic presidential candidate.[1] As of the 2020 presidential election, this (and the prior election) mark the last time that Montana has voted Democratic in two consecutive presidential elections.
^Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
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