1944 United States presidential election in Iowa information
Main article: 1944 United States presidential election
1944 United States presidential election in Iowa
← 1940
November 7, 1944[1]
1948 →
All 10 Iowa votes to the Electoral College
Nominee
Thomas E. Dewey
Franklin D. Roosevelt
Party
Republican
Democratic
Home state
New York
New York
Running mate
John W. Bricker
Harry S. Truman
Electoral vote
10
0
Popular vote
547,267
499,876
Percentage
51.99%
47.49%
County Results
Dewey
40-50%
50-60%
60-70%
Roosevelt
50-60%
President before election
Franklin D. Roosevelt
Democratic
Elected President
Franklin D. Roosevelt
Democratic
Elections in Iowa
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v
t
e
The 1944 United States presidential election in Iowa took place on November 7, 1944, as part of the 1944 United States presidential election. Iowa voters chose ten[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Iowa was won by Governor Thomas E. Dewey (R–New York), running with Governor John Bricker, with 51.99% of the popular vote, against incumbent President Franklin D. Roosevelt (D–New York), running with Senator Harry S. Truman, with 47.49% of the popular vote.[3][4] This is the last election in which an incumbent president of either party won another term in office without winning Iowa.
^"United States Presidential election of 1944 - Encyclopædia Britannica". Retrieved December 22, 2017.
^"1944 Election for the Fortieth Term (1945-49)". Retrieved December 22, 2017.
^"1944 Presidential General Election Results - Iowa". Retrieved December 22, 2017.
^"The American Presidency Project - Election of 1944". Retrieved December 22, 2017.
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