1932 United States presidential election in Nevada information
Election in Nevada
Main article: 1932 United States presidential election
1932 United States presidential election in Nevada
← 1928
November 8, 1932[1]
1936 →
All 3 Nevada votes to the Electoral College
Nominee
Franklin D. Roosevelt
Herbert Hoover
Party
Democratic
Republican
Home state
New York
California
Running mate
John Nance Garner
Charles Curtis
Electoral vote
3
0
Popular vote
28,756
12,674
Percentage
69.41%
30.59%
County Results
Roosevelt
50-60%
60-70%
70-80%
80-90%
President before election
Herbert Hoover
Republican
Elected President
Franklin D. Roosevelt
Democratic
Elections in Nevada
Federal government
U.S. President
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1896
1900
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1916
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GOP
1920
Dem
GOP
1924
Dem
GOP
1928
Dem
GOP
1932
Dem
GOP
1936
Dem
GOP
1940
Dem
GOP
1944
Dem
GOP
1948
Dem
GOP
1952
Dem
GOP
1956
Dem
GOP
1960
Dem
GOP
1964
Dem
GOP
1968
Dem
GOP
1972
Dem
GOP
1976
Dem
GOP
1980
Dem
GOP
1984
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GOP
1988
Dem
GOP
1992
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GOP
1996
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GOP
2000
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GOP
2004
Dem
GOP
2008
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GOP
2012
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GOP
2016
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GOP
2020
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GOP
2024
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2nd
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Special elections
2nd district, 2011
State government
General
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Gubernatorial
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2002 Nevada Question 2
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Mayoral
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Mayoral
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North Las Vegas
Mayoral
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Reno
Mayoral
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None of These Candidates
Nevada portal
v
t
e
The 1932 United States presidential election in Nevada took place on November 8, 1932, as part of the 1932 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Nevada was won by Governor Franklin D. Roosevelt (D–New York), running with Speaker John Nance Garner, with 69.41% of the popular vote, against incumbent President Herbert Hoover (R–California), running with Vice President Charles Curtis, with 30.59% of the popular vote.[3]
^"United States Presidential election of 1932 - Encyclopædia Britannica". Retrieved January 25, 2019.
^"1932 Election for the Thirty-seventh Term (1933-37)". Retrieved January 25, 2019.
^"1932 Presidential General Election Results – Nevada". Retrieved January 25, 2019.
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