1920 United States presidential election in Iowa information
Main article: 1920 United States presidential election
1920 United States presidential election in Iowa
← 1916
November 2, 1920
1924 →
Nominee
Warren G. Harding
James M. Cox
Party
Republican
Democratic
Home state
Ohio
Ohio
Running mate
Calvin Coolidge
Franklin D. Roosevelt
Electoral vote
13
0
Popular vote
634,674
227,921
Percentage
70.91%
25.46%
County Results
Harding
50-60%
60-70%
70-80%
80-90%
President before election
Woodrow Wilson
Democratic
Elected President
Warren G. Harding
Republican
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v
t
e
The 1920 United States presidential election in Iowa took place on November 2, 1920, as part of the 1920 United States presidential election which was held throughout all contemporary 48 states. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.
Iowa voted for the Republican nominee, Senator Warren G. Harding of Ohio, over the Democratic nominee, Governor James M. Cox of Ohio. Harding ran with Governor Calvin Coolidge of Massachusetts, while Cox ran with Assistant Secretary of the Navy Franklin D. Roosevelt of New York. Harding won the state by a margin of 45.45%.
With 70.91 percent of the popular, Iowa would prove to be Harding's fifth strongest state in the 1920 election terms of popular vote percentage after North Dakota, Vermont, Michigan, and Wisconsin.[1] Harding's performance is, by a margin of 6.79 percent, the best by any candidate in Iowa presidential election history,[2] and he and Dwight D. Eisenhower in 1952 are the only presidential candidates to sweep all of Iowa's counties.
^"1920 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
^"Presidential General Election Results Comparison – Iowa". Dave Leip’s U.S. Election Atlas.
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