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1912 United States presidential election in Ohio information


1912 United States presidential election in Ohio
1912 United States presidential election in Ohio
← 1908 November 5, 1912 1916 →
 
Nominee Woodrow Wilson William Howard Taft
Party Democratic Republican
Home state New Jersey Ohio
Running mate Thomas R. Marshall Nicholas M. Butler
Electoral vote 24 0
Popular vote 424,834 278,168
Percentage 40.96% 26.82%

 
Nominee Theodore Roosevelt Eugene V. Debs
Party Progressive Socialist
Home state New York Indiana
Running mate Hiram Johnson Emil Seidel
Electoral vote 0 0
Popular vote 229,807 90,144
Percentage 22.16% 8.69%

County Results

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

The 1912 United States presidential election in Ohio took place on November 5, 1912 as part of the 1912 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.

Ohio was won by the Democratic nominee Woodrow Wilson and his running mate Thomas R. Marshall. As a result of his victory, Wilson became the first Democratic presidential candidate since Franklin Pierce in 1852 to win the state.

Ohio had been a Republican state since 1856, but broke tradition due to the strong performance by the Progressive Party (also known as the Bull Moose Party) led by Theodore Roosevelt, which ultimately split the Republican vote. Theodore Roosevelt was able to gain 22.16 percent of the popular vote - though trailed the Republican Party nominee William Howard Taft, an Ohio native, who won 26.82% of the popular vote, and Wilson of the Democratic Party who won 40.96% of the popular vote. It marked Ohio's shift from a reliably Republican state to a bellwether state, as it would vote for the winning candidate in every presidential election thereafter except 1944, 1960, and 2020.

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