1900 United States presidential election in Nebraska information
Election in Nebraska
Main article: 1900 United States presidential election
1900 United States presidential election in Nebraska
← 1896
November 6, 1900
1904 →
Nominee
William McKinley
William Jennings Bryan
Party
Republican
Democratic
Home state
Ohio
Nebraska
Running mate
Theodore Roosevelt
Adlai Stevenson I
Electoral vote
8
0
Popular vote
121,835
114,013
Percentage
50.46%
47.22%
County Results
McKinley
40-50%
50-60%
60-70%
70-80%
Bryan
40-50%
50-60%
60-70%
President before election
William McKinley
Republican
Elected President
William McKinley
Republican
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v
t
e
The 1900 United States presidential election in Nebraska took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Voters chose eight electors to the Electoral College, which selected the president and vice president.
Nebraska was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. They defeated the Democratic nominees, former U.S. Representative, 1896 Democratic presidential nominee and Nebraska native William Jennings Bryan and his running mate, former Vice President Adlai Stevenson I. McKinley won the state by a narrow margin of 3.24% in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.
Bryan had previously defeated McKinley in the state four years earlier and would later win it again against William Howard Taft in 1908.
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