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1891 Canadian federal election information


1891 Canadian federal election
1891 Canadian federal election
← 1887 March 5, 1891 1896 →
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215 seats in the House of Commons
108 seats needed for a majority
Turnout64.4%[1] (Decrease5.7pp)
  First party Second party
 
Leader John A. Macdonald Wilfrid Laurier
Party Conservative Liberal
Leader since 1867 1887
Leader's seat Kingston Quebec East[b]
Last election 122 seats, 47.4% 80 seats, 43.1%
Seats won 117 90
Seat change Decrease5 Increase10
Popular vote 376,518 350,512
Percentage 48.6%[a] 45.2%
Swing Increase1.2% Increase2.1%

1891 Canadian electoral map

The Canadian parliament after the 1891 election

Prime Minister before election

John A. Macdonald
Conservative

Prime Minister after election

John A. Macdonald
Conservative

The 1891 Canadian federal election was held on March 5, 1891, to elect members of the House of Commons of Canada of the 7th Parliament of Canada. It was won by the Conservative Party of Prime Minister Sir John A. Macdonald.

A Conservative election poster from 1891.

The main issue of the 1891 campaign was Macdonald's National Policy, a policy of protective tariffs. The Liberals supported reciprocity (free trade) with the United States.

Macdonald led a Conservative campaign emphasizing stability, and retained the Conservatives' majority in the House of Commons. It was a close election and he campaigned hard. Macdonald died a few months after the election, which led to his succession by four different Conservative Prime Ministers until the 1896 election.

It was Wilfrid Laurier's first election as leader of the Liberals. Although he lost the election, he increased the Liberals' support. He returned in 1896 to win a solid majority, despite losing the popular vote.

Canadian voters would return to the issue of free trade 20 years later in the 1911 federal election.

  1. ^ "Voter Turnout at Federal Elections and Referendums". Elections Canada. Retrieved March 10, 2019.


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