1864 United States presidential election in Iowa information
Main article: 1864 United States presidential election
1864 United States presidential election in Iowa
← 1860
November 8, 1864
1868 →
Turnout
19.70% of the total population 0.63 pp[1]
Nominee
Abraham Lincoln
George B. McClellan
Party
National Union
Democratic
Home state
Illinois
New Jersey
Running mate
Andrew Johnson
George H. Pendleton
Electoral vote
8
0
Popular vote
88,500
49,525
Percentage
64.12%
35.88%
County Results
Lincoln
50-60%
60-70%
70-80%
80-90%
90-100%
McClellan
50-60%
60-70%
70-80%
80-90%
Tie
~50%
President before election
Abraham Lincoln
Republican
Elected President
Abraham Lincoln
National Union
Elections in Iowa
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Question 1
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Cedar Rapids
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v
t
e
The 1864 United States presidential election in Iowa took place on November 8, 1864, as part of the 1864 United States presidential election. Iowa voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Iowa was won by the National Union candidate Republican incumbent President Abraham Lincoln of Illinois and his running mate former Senator and Military Governor of Tennessee Andrew Johnson. They defeated the Democratic candidate 4th Commanding General of the United States Army George B. McClellan of New Jersey and his running mate Representative George H. Pendleton of Ohio. Lincoln won the state by a margin of 28.24%.[2]
^"1880 Presidential Election Results Iowa Total Population Turnout".
^ ab"1864 Presidential Election Results Iowa".
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Global Information
0.63 pp[1]
