1836 United States presidential election in Indiana information
Election in Indiana
Main article: 1836 United States presidential election
1836 United States presidential election in Indiana
← 1832
November 3 – December 7, 1836
1840 →
Nominee
William Henry Harrison
Martin Van Buren
Party
Whig
Democratic
Home state
Ohio
New York
Running mate
Francis Granger
Richard Johnson
Electoral vote
9
0
Popular vote
41,281/41,339
32,478/33,084
Percentage
55.97%/55.55%
44.03%/44.45
Elections in Indiana
Federal government
Presidential elections
1816
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1836
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U.S. Senate elections
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1990
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7th sp
2010
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2012
2014
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2nd sp
2024
State government
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Gubernatorial elections
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City-County Council elections
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Other localities
Carmel (mayoral)
Evansville (mayoral)
Fort Wayne (mayoral)
Gary (mayoral)
South Bend (mayoral)
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The 1836 United States presidential election in Indiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Indiana voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Indiana by a margin of 11.94%./11.10%
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